140033114104957 has 2 divisors, whose sum is σ = 140033114104958. Its totient is φ = 140033114104956.

The previous prime is 140033114104943. The next prime is 140033114104981. The reversal of 140033114104957 is 759401411330041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 139045344479001 + 987769625956 = 11791749^2 + 993866^2 .

It is an emirp because it is prime and its reverse (759401411330041) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140033114104957 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140033114104937) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70016557052478 + 70016557052479.

It is an arithmetic number, because the mean of its divisors is an integer number (70016557052479).

Almost surely, 2^{140033114104957} is an apocalyptic number.

It is an amenable number.

140033114104957 is a deficient number, since it is larger than the sum of its proper divisors (1).

140033114104957 is an equidigital number, since it uses as much as digits as its factorization.

140033114104957 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 181440, while the sum is 43.

Adding to 140033114104957 its reverse (759401411330041), we get a palindrome (899434525434998).

The spelling of 140033114104957 in words is "one hundred forty trillion, thirty-three billion, one hundred fourteen million, one hundred four thousand, nine hundred fifty-seven".