Base | Representation |
---|---|
bin | 1000001001101010100… |
… | …0101100000111101101 |
3 | 111101110011101021010211 |
4 | 2002122220230013231 |
5 | 4243242011424323 |
6 | 144155211502421 |
7 | 13055104335355 |
oct | 2023250540755 |
9 | 441404337124 |
10 | 140033311213 |
11 | 5442a176374 |
12 | 23180a57a11 |
13 | 10288756183 |
14 | 6ac5c1db65 |
15 | 3998b0170d |
hex | 209aa2c1ed |
140033311213 has 4 divisors (see below), whose sum is σ = 140035728348. Its totient is φ = 140030894080.
The previous prime is 140033311189. The next prime is 140033311237. The reversal of 140033311213 is 312113330041.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 312113330041 = 2531 ⋅123316211.
It is an interprime number because it is at equal distance from previous prime (140033311189) and next prime (140033311237).
It can be written as a sum of positive squares in 2 ways, for example, as 69065416809 + 70967894404 = 262803^2 + 266398^2 .
It is a cyclic number.
It is not a de Polignac number, because 140033311213 - 217 = 140033180141 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (140033311273) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1119478 + ... + 1238263.
It is an arithmetic number, because the mean of its divisors is an integer number (35008932087).
Almost surely, 2140033311213 is an apocalyptic number.
It is an amenable number.
140033311213 is a deficient number, since it is larger than the sum of its proper divisors (2417135).
140033311213 is an equidigital number, since it uses as much as digits as its factorization.
140033311213 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2417134.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 140033311213 its reverse (312113330041), we get a palindrome (452146641254).
The spelling of 140033311213 in words is "one hundred forty billion, thirty-three million, three hundred eleven thousand, two hundred thirteen".
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