140035433 has 2 divisors, whose sum is σ = 140035434. Its totient is φ = 140035432.

The previous prime is 140035429. The next prime is 140035447. The reversal of 140035433 is 334530041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 98148649 + 41886784 = 9907^2 + 6472^2 .

It is an emirp because it is prime and its reverse (334530041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140035433 - 2² = 140035429 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 140035399 and 140035408.

It is not a weakly prime, because it can be changed into another prime (140035033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70017716 + 70017717.

It is an arithmetic number, because the mean of its divisors is an integer number (70017717).

Almost surely, 2^140035433 is an apocalyptic number.

It is an amenable number.

140035433 is a deficient number, since it is larger than the sum of its proper divisors (1).

140035433 is an equidigital number, since it uses as much as digits as its factorization.

140035433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 23.

The square root of 140035433 is about 11833.6567890065. The cubic root of 140035433 is about 519.2932125956.

Adding to 140035433 its reverse (334530041), we get a palindrome (474565474).

The spelling of 140035433 in words is "one hundred forty million, thirty-five thousand, four hundred thirty-three".