Base | Representation |
---|---|
bin | 1000001001101011011… |
… | …1111110110110110011 |
3 | 111101110102220221022200 |
4 | 2002122313332312303 |
5 | 4243244023220430 |
6 | 144155433434243 |
7 | 13055153403210 |
oct | 2023267766663 |
9 | 441412827280 |
10 | 140037320115 |
11 | 54431464310 |
12 | 2318226b983 |
13 | 1028952aac4 |
14 | 6ac6584b07 |
15 | 3999144460 |
hex | 209adfedb3 |
140037320115 has 192 divisors, whose sum is σ = 306946298880. Its totient is φ = 57370705920.
The previous prime is 140037320081. The next prime is 140037320119. The reversal of 140037320115 is 511023730041.
It is not a de Polignac number, because 140037320115 - 26 = 140037320051 is a prime.
It is a super-2 number, since 2×1400373201152 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (140037320119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 177937752 + ... + 177938538.
It is an arithmetic number, because the mean of its divisors is an integer number (1598678640).
Almost surely, 2140037320115 is an apocalyptic number.
140037320115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
140037320115 is an abundant number, since it is smaller than the sum of its proper divisors (166908978765).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
140037320115 is a wasteful number, since it uses less digits than its factorization.
140037320115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1482 (or 1479 counting only the distinct ones).
The product of its (nonzero) digits is 2520, while the sum is 27.
The spelling of 140037320115 in words is "one hundred forty billion, thirty-seven million, three hundred twenty thousand, one hundred fifteen".
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