Base | Representation |
---|---|
bin | 10100011000001110011… |
… | …011000110100001000101 |
3 | 11221212200101011011122110 |
4 | 110120032123012201011 |
5 | 140421010214332401 |
6 | 2551200244251233 |
7 | 203114151565113 |
oct | 24301633064105 |
9 | 4855611134573 |
10 | 1400401324101 |
11 | 49a9a8047aaa |
12 | 1a74a76a0b19 |
13 | a2098ac0060 |
14 | 4bacba36ab3 |
15 | 266634d59d6 |
hex | 1460e6c6845 |
1400401324101 has 16 divisors (see below), whose sum is σ = 2011589625024. Its totient is φ = 861461021184.
The previous prime is 1400401324097. The next prime is 1400401324103. The reversal of 1400401324101 is 1014231040041.
It is not a de Polignac number, because 1400401324101 - 22 = 1400401324097 is a prime.
It is a super-2 number, since 2×14004013241012 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1400401324103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6653571 + ... + 6860816.
It is an arithmetic number, because the mean of its divisors is an integer number (125724351564).
Almost surely, 21400401324101 is an apocalyptic number.
It is an amenable number.
1400401324101 is a deficient number, since it is larger than the sum of its proper divisors (611188300923).
1400401324101 is a wasteful number, since it uses less digits than its factorization.
1400401324101 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13517060.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 1400401324101 its reverse (1014231040041), we get a palindrome (2414632364142).
The spelling of 1400401324101 in words is "one trillion, four hundred billion, four hundred one million, three hundred twenty-four thousand, one hundred one".
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