Base | Representation |
---|---|
bin | 11111110101110110100110… |
… | …101011100110101010100111 |
3 | 200100211201020200021222201212 |
4 | 133311312212223212222213 |
5 | 121323404320003301003 |
6 | 1213501325422342035 |
7 | 41332366555220462 |
oct | 3765664653465247 |
9 | 610751220258655 |
10 | 140040205134503 |
11 | 40691798a59933 |
12 | 1385889142a91b |
13 | 601a97212730b |
14 | 2681da6c162d9 |
15 | 112cb78ee3dd8 |
hex | 7f5da6ae6aa7 |
140040205134503 has 8 divisors (see below), whose sum is σ = 151432712436672. Its totient is φ = 128998236518656.
The previous prime is 140040205134497. The next prime is 140040205134509. The reversal of 140040205134503 is 305431502040041.
It is an interprime number because it is at equal distance from previous prime (140040205134497) and next prime (140040205134509).
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 140040205134503 - 244 = 122448019090087 is a prime.
It is a super-2 number, since 2×1400402051345032 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 140040205134503.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (140040205134509) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 87634670750 + ... + 87634672347.
It is an arithmetic number, because the mean of its divisors is an integer number (18929089054584).
Almost surely, 2140040205134503 is an apocalyptic number.
140040205134503 is a deficient number, since it is larger than the sum of its proper divisors (11392507302169).
140040205134503 is a wasteful number, since it uses less digits than its factorization.
140040205134503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 175269343161.
The product of its (nonzero) digits is 28800, while the sum is 32.
Adding to 140040205134503 its reverse (305431502040041), we get a palindrome (445471707174544).
The spelling of 140040205134503 in words is "one hundred forty trillion, forty billion, two hundred five million, one hundred thirty-four thousand, five hundred three".
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