Base | Representation |
---|---|
bin | 10100011000001110011… |
… | …111001111111010000111 |
3 | 11221212200110012101210021 |
4 | 110120032133033322013 |
5 | 140421011004124033 |
6 | 2551200323440011 |
7 | 203114164043251 |
oct | 24301637177207 |
9 | 4855613171707 |
10 | 1400402411143 |
11 | 49a9a871a78a |
12 | 1a74a7b26007 |
13 | a20990b0a88 |
14 | 4bacbc3acd1 |
15 | 2666364cb2d |
hex | 1460e7cfe87 |
1400402411143 has 2 divisors, whose sum is σ = 1400402411144. Its totient is φ = 1400402411142.
The previous prime is 1400402410997. The next prime is 1400402411171. The reversal of 1400402411143 is 3411142040041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1400402411143 - 229 = 1399865540231 is a prime.
It is a super-2 number, since 2×14004024111432 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1400402411173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700201205571 + 700201205572.
It is an arithmetic number, because the mean of its divisors is an integer number (700201205572).
Almost surely, 21400402411143 is an apocalyptic number.
1400402411143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1400402411143 is an equidigital number, since it uses as much as digits as its factorization.
1400402411143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 1400402411143 its reverse (3411142040041), we get a palindrome (4811544451184).
The spelling of 1400402411143 in words is "one trillion, four hundred billion, four hundred two million, four hundred eleven thousand, one hundred forty-three".
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