Base | Representation |
---|---|
bin | 1000001001101101010… |
… | …1010010011100100111 |
3 | 111101110222101020121202 |
4 | 2002123111102130213 |
5 | 4243303010040120 |
6 | 144200310233115 |
7 | 13055305611014 |
oct | 2023325223447 |
9 | 441428336552 |
10 | 140045002535 |
11 | 54435831219 |
12 | 2318495579b |
13 | 1028acba809 |
14 | 6ac75c470b |
15 | 3999b60875 |
hex | 209b552727 |
140045002535 has 8 divisors (see below), whose sum is σ = 171629620416. Its totient is φ = 109652257120.
The previous prime is 140045002523. The next prime is 140045002597. The reversal of 140045002535 is 535200540041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-140045002535 is a prime.
It is a super-2 number, since 2×1400450025352 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 140045002498 and 140045002507.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 297967856 + ... + 297968325.
It is an arithmetic number, because the mean of its divisors is an integer number (21453702552).
Almost surely, 2140045002535 is an apocalyptic number.
140045002535 is a deficient number, since it is larger than the sum of its proper divisors (31584617881).
140045002535 is an equidigital number, since it uses as much as digits as its factorization.
140045002535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 595936233.
The product of its (nonzero) digits is 12000, while the sum is 29.
Adding to 140045002535 its reverse (535200540041), we get a palindrome (675245542576).
The spelling of 140045002535 in words is "one hundred forty billion, forty-five million, two thousand, five hundred thirty-five".
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