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14005003331 = 113141070391
BaseRepresentation
bin11010000101100001…
…10110010001000011
31100011000212212212002
431002300312101003
5212140240101311
610233411454215
71004025364334
oct150260662103
940130785762
1014005003331
115a37506320
12286a2b736b
131422671327
1496c01a28b
1556e7c093b
hex342c36443

14005003331 has 8 divisors (see below), whose sum is σ = 15771030528. Its totient is φ = 12321117000.

The previous prime is 14005003289. The next prime is 14005003349. The reversal of 14005003331 is 13330050041.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14005003331 - 218 = 14004741187 is a prime.

It is a super-2 number, since 2×140050033312 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (14005009331) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20534855 + ... + 20535536.

It is an arithmetic number, because the mean of its divisors is an integer number (1971378816).

Almost surely, 214005003331 is an apocalyptic number.

14005003331 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

14005003331 is a deficient number, since it is larger than the sum of its proper divisors (1766027197).

14005003331 is a wasteful number, since it uses less digits than its factorization.

14005003331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41070433.

The product of its (nonzero) digits is 540, while the sum is 20.

Adding to 14005003331 its reverse (13330050041), we get a palindrome (27335053372).

The spelling of 14005003331 in words is "fourteen billion, five million, three thousand, three hundred thirty-one".

Divisors: 1 11 31 341 41070391 451774301 1273182121 14005003331