Base | Representation |
---|---|
bin | 1000001001101110100… |
… | …0100001010110101111 |
3 | 111101111022212101200002 |
4 | 2002123220201112233 |
5 | 4243310302404320 |
6 | 144201010254515 |
7 | 13055366510105 |
oct | 2023350412657 |
9 | 441438771602 |
10 | 140050044335 |
11 | 544386651a3 |
12 | 2318658743b |
13 | 1028c064626 |
14 | 6ac8137c75 |
15 | 399a309675 |
hex | 209ba215af |
140050044335 has 16 divisors (see below), whose sum is σ = 179903721600. Its totient is φ = 104344150176.
The previous prime is 140050044313. The next prime is 140050044347. The reversal of 140050044335 is 533440050041.
It is a cyclic number.
It is not a de Polignac number, because 140050044335 - 26 = 140050044271 is a prime.
It is a super-2 number, since 2×1400500443352 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 140050044298 and 140050044307.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12487709 + ... + 12498918.
It is an arithmetic number, because the mean of its divisors is an integer number (11243982600).
Almost surely, 2140050044335 is an apocalyptic number.
140050044335 is a deficient number, since it is larger than the sum of its proper divisors (39853677265).
140050044335 is a wasteful number, since it uses less digits than its factorization.
140050044335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24986710.
The product of its (nonzero) digits is 14400, while the sum is 29.
Adding to 140050044335 its reverse (533440050041), we get a palindrome (673490094376).
The spelling of 140050044335 in words is "one hundred forty billion, fifty million, forty-four thousand, three hundred thirty-five".
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