Base | Representation |
---|---|
bin | 1000001001101111010… |
… | …1010101101100010011 |
3 | 111101111120012002212020 |
4 | 2002123311111230103 |
5 | 4243312132420220 |
6 | 144201210302523 |
7 | 13055440203240 |
oct | 2023365255423 |
9 | 441446162766 |
10 | 140053404435 |
11 | 5443a54a73a |
12 | 23187727a43 |
13 | 1028c96cb59 |
14 | 6ac87705c7 |
15 | 399a770040 |
hex | 209bd55b13 |
140053404435 has 32 divisors (see below), whose sum is σ = 271162225152. Its totient is φ = 60258270720.
The previous prime is 140053404383. The next prime is 140053404487. The reversal of 140053404435 is 534404350041.
It is a happy number.
140053404435 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (140053404383) and next prime (140053404487).
It is not a de Polignac number, because 140053404435 - 29 = 140053403923 is a prime.
It is a super-2 number, since 2×1400534044352 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 140053404396 and 140053404405.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 39228861 + ... + 39232430.
It is an arithmetic number, because the mean of its divisors is an integer number (8473819536).
Almost surely, 2140053404435 is an apocalyptic number.
140053404435 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
140053404435 is a deficient number, since it is larger than the sum of its proper divisors (131108820717).
140053404435 is a wasteful number, since it uses less digits than its factorization.
140053404435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 78461323.
The product of its (nonzero) digits is 57600, while the sum is 33.
Adding to 140053404435 its reverse (534404350041), we get a palindrome (674457754476).
The spelling of 140053404435 in words is "one hundred forty billion, fifty-three million, four hundred four thousand, four hundred thirty-five".
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