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14006124331243 = 111273284030113
BaseRepresentation
bin1100101111010000111000…
…0100001100000011101011
31211120222020212221012211121
43023310032010030003223
53313434020312044433
645442154044440111
72643623550326512
oct313641604140353
954528225835747
1014006124331243
11450aa67056370
1216a2592849037
137a7a05a021a5
14365c859a3679
151944e88e4c2d
hexcbd0e10c0eb

14006124331243 has 4 divisors (see below), whose sum is σ = 15279408361368. Its totient is φ = 12732840301120.

The previous prime is 14006124331219. The next prime is 14006124331261. The reversal of 14006124331243 is 34213342160041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14006124331243 - 25 = 14006124331211 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14006124331199 and 14006124331208.

It is not an unprimeable number, because it can be changed into a prime (14006124331943) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 636642015046 + ... + 636642015067.

It is an arithmetic number, because the mean of its divisors is an integer number (3819852090342).

Almost surely, 214006124331243 is an apocalyptic number.

14006124331243 is a deficient number, since it is larger than the sum of its proper divisors (1273284030125).

14006124331243 is a wasteful number, since it uses less digits than its factorization.

14006124331243 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1273284030124.

The product of its (nonzero) digits is 41472, while the sum is 34.

Adding to 14006124331243 its reverse (34213342160041), we get a palindrome (48219466491284).

The spelling of 14006124331243 in words is "fourteen trillion, six billion, one hundred twenty-four million, three hundred thirty-one thousand, two hundred forty-three".

Divisors: 1 11 1273284030113 14006124331243