Base | Representation |
---|---|
bin | 11010000110001010… |
… | …01011000101001111 |
3 | 1100011101220120200121 |
4 | 31003011023011033 |
5 | 212143121101341 |
6 | 10234122005411 |
7 | 1004121565303 |
oct | 150305130517 |
9 | 40141816617 |
10 | 14010331471 |
11 | 5a3a515444 |
12 | 2870046867 |
13 | 14237b8586 |
14 | 96ca05d03 |
15 | 56eec44d1 |
hex | 34314b14f |
14010331471 has 4 divisors (see below), whose sum is σ = 14011156744. Its totient is φ = 14009506200.
The previous prime is 14010331457. The next prime is 14010331507. The reversal of 14010331471 is 17413301041.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14010331471 - 211 = 14010329423 is a prime.
It is a super-3 number, since 3×140103314713 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14010331421) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 386625 + ... + 421306.
It is an arithmetic number, because the mean of its divisors is an integer number (3502789186).
Almost surely, 214010331471 is an apocalyptic number.
14010331471 is a deficient number, since it is larger than the sum of its proper divisors (825273).
14010331471 is an equidigital number, since it uses as much as digits as its factorization.
14010331471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 825272.
The product of its (nonzero) digits is 1008, while the sum is 25.
The spelling of 14010331471 in words is "fourteen billion, ten million, three hundred thirty-one thousand, four hundred seventy-one".
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