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14010413435 = 52802082687
BaseRepresentation
bin11010000110001010…
…11111000101111011
31100011102001202010022
431003011133011323
5212143131212220
610234123441055
71004122356254
oct150305370573
940142052108
1014010413435
115a3a570a87
12287008618b
131423816985
1496ca27b2b
1556eedd925
hex34315f17b

14010413435 has 4 divisors (see below), whose sum is σ = 16812496128. Its totient is φ = 11208330744.

The previous prime is 14010413353. The next prime is 14010413551. The reversal of 14010413435 is 53431401041.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53431401041 = 113472844257.

It is a cyclic number.

It is not a de Polignac number, because 14010413435 - 218 = 14010151291 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1401041339 + ... + 1401041348.

It is an arithmetic number, because the mean of its divisors is an integer number (4203124032).

Almost surely, 214010413435 is an apocalyptic number.

14010413435 is a deficient number, since it is larger than the sum of its proper divisors (2802082693).

14010413435 is an equidigital number, since it uses as much as digits as its factorization.

14010413435 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2802082692.

The product of its (nonzero) digits is 2880, while the sum is 26.

Adding to 14010413435 its reverse (53431401041), we get a palindrome (67441814476).

The spelling of 14010413435 in words is "fourteen billion, ten million, four hundred thirteen thousand, four hundred thirty-five".

Divisors: 1 5 2802082687 14010413435