140105555012301 has 4 divisors (see below), whose sum is σ = 186807406683072. Its totient is φ = 93403703341532.

The previous prime is 140105555012287. The next prime is 140105555012341. The reversal of 140105555012301 is 103210555501041.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140105555012301 - 2¹⁹ = 140105554488013 is a prime.

It is a super-2 number, since 2×140105555012301² (a number of 29 digits) contains 22 as substring.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140105555012341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23350925835381 + ... + 23350925835386.

It is an arithmetic number, because the mean of its divisors is an integer number (46701851670768).

Almost surely, 2^{140105555012301} is an apocalyptic number.

It is an amenable number.

140105555012301 is a deficient number, since it is larger than the sum of its proper divisors (46701851670771).

140105555012301 is an equidigital number, since it uses as much as digits as its factorization.

140105555012301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 46701851670770.

The product of its (nonzero) digits is 15000, while the sum is 33.

The spelling of 140105555012301 in words is "one hundred forty trillion, one hundred five billion, five hundred fifty-five million, twelve thousand, three hundred one".