140109776113 has 2 divisors, whose sum is σ = 140109776114. Its totient is φ = 140109776112.

The previous prime is 140109776111. The next prime is 140109776123. The reversal of 140109776113 is 311677901041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 139541096704 + 568679409 = 373552^2 + 23847^2 .

It is a cyclic number.

It is not a de Polignac number, because 140109776113 - 2¹ = 140109776111 is a prime.

Together with 140109776111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (140109776111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70054888056 + 70054888057.

It is an arithmetic number, because the mean of its divisors is an integer number (70054888057).

Almost surely, 2^140109776113 is an apocalyptic number.

It is an amenable number.

140109776113 is a deficient number, since it is larger than the sum of its proper divisors (1).

140109776113 is an equidigital number, since it uses as much as digits as its factorization.

140109776113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31752, while the sum is 40.

The spelling of 140109776113 in words is "one hundred forty billion, one hundred nine million, seven hundred seventy-six thousand, one hundred thirteen".