14011143311 has 4 divisors (see below), whose sum is σ = 15284883624. Its totient is φ = 12737403000.

The previous prime is 14011143299. The next prime is 14011143319. The reversal of 14011143311 is 11334111041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14011143311 - 2¹⁰ = 14011142287 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14011143319) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 636870140 + ... + 636870161.

It is an arithmetic number, because the mean of its divisors is an integer number (3821220906).

Almost surely, 2^14011143311 is an apocalyptic number.

14011143311 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

14011143311 is a deficient number, since it is larger than the sum of its proper divisors (1273740313).

14011143311 is a wasteful number, since it uses less digits than its factorization.

14011143311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1273740312.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 14011143311 its reverse (11334111041), we get a palindrome (25345254352).

The spelling of 14011143311 in words is "fourteen billion, eleven million, one hundred forty-three thousand, three hundred eleven".