14011204343 has 4 divisors (see below), whose sum is σ = 14188561440. Its totient is φ = 13833847248.

The previous prime is 14011204327. The next prime is 14011204379. The reversal of 14011204343 is 34340211041.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34340211041 = 63839 ⋅537919.

It is a cyclic number.

It is not a de Polignac number, because 14011204343 - 2⁴ = 14011204327 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14011204843) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88678430 + ... + 88678587.

It is an arithmetic number, because the mean of its divisors is an integer number (3547140360).

Almost surely, 2^14011204343 is an apocalyptic number.

14011204343 is a deficient number, since it is larger than the sum of its proper divisors (177357097).

14011204343 is an equidigital number, since it uses as much as digits as its factorization.

14011204343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 177357096.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 14011204343 its reverse (34340211041), we get a palindrome (48351415384).

The spelling of 14011204343 in words is "fourteen billion, eleven million, two hundred four thousand, three hundred forty-three".