14011206343 has 4 divisors (see below), whose sum is σ = 14039062128. Its totient is φ = 13983350560.

The previous prime is 14011206283. The next prime is 14011206367. The reversal of 14011206343 is 34360211041.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34360211041 = 13 ⋅2643093157.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14011206343 is a prime.

It is a super-2 number, since 2×14011206343² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14011266343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13927138 + ... + 13928143.

It is an arithmetic number, because the mean of its divisors is an integer number (3509765532).

Almost surely, 2^14011206343 is an apocalyptic number.

14011206343 is a deficient number, since it is larger than the sum of its proper divisors (27855785).

14011206343 is an equidigital number, since it uses as much as digits as its factorization.

14011206343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27855784.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 14011206343 its reverse (34360211041), we get a palindrome (48371417384).

The spelling of 14011206343 in words is "fourteen billion, eleven million, two hundred six thousand, three hundred forty-three".