14011213431 has 4 divisors (see below), whose sum is σ = 18681617912. Its totient is φ = 9340808952.

The previous prime is 14011213427. The next prime is 14011213457. The reversal of 14011213431 is 13431211041.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13431211041 = 3 ⋅4477070347.

It is not a de Polignac number, because 14011213431 - 2² = 14011213427 is a prime.

It is a super-2 number, since 2×14011213431² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14011213398 and 14011213407.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14011212431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2335202236 + ... + 2335202241.

It is an arithmetic number, because the mean of its divisors is an integer number (4670404478).

Almost surely, 2^14011213431 is an apocalyptic number.

14011213431 is a deficient number, since it is larger than the sum of its proper divisors (4670404481).

14011213431 is an equidigital number, since it uses as much as digits as its factorization.

14011213431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4670404480.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 14011213431 its reverse (13431211041), we get a palindrome (27442424472).

The spelling of 14011213431 in words is "fourteen billion, eleven million, two hundred thirteen thousand, four hundred thirty-one".