1401123000101 has 4 divisors (see below), whose sum is σ = 1528497818304. Its totient is φ = 1273748181900.

The previous prime is 1401123000059. The next prime is 1401123000103. The reversal of 1401123000101 is 1010003211041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1401123000101 - 2¹⁰ = 1401122999077 is a prime.

It is a super-2 number, since 2×1401123000101² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1401123000103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63687409085 + ... + 63687409106.

It is an arithmetic number, because the mean of its divisors is an integer number (382124454576).

Almost surely, 2^{1401123000101} is an apocalyptic number.

1401123000101 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1401123000101 is a deficient number, since it is larger than the sum of its proper divisors (127374818203).

1401123000101 is a wasteful number, since it uses less digits than its factorization.

1401123000101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 127374818202.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 1401123000101 its reverse (1010003211041), we get a palindrome (2411126211142).

The spelling of 1401123000101 in words is "one trillion, four hundred one billion, one hundred twenty-three million, one hundred one", and thus it is an aban number.