Base | Representation |
---|---|
bin | 1100101111100011111001… |
… | …1101000011001011011111 |
3 | 1211121110102210021001222022 |
4 | 3023320332131003023133 |
5 | 3314030000131402033 |
6 | 45444400513010355 |
7 | 2644164240331643 |
oct | 313707635031337 |
9 | 54543383231868 |
10 | 14011231122143 |
11 | 4512147772a12 |
12 | 16a3578b539bb |
13 | 7a833aa11558 |
14 | 36620bd02c23 |
15 | 1946e6de3098 |
hex | cbe3e7432df |
14011231122143 has 8 divisors (see below), whose sum is σ = 14016082203648. Its totient is φ = 14006380313304.
The previous prime is 14011231122139. The next prime is 14011231122149. The reversal of 14011231122143 is 34122113211041.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14011231122143 - 22 = 14011231122139 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14011231122149) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 204380930 + ... + 204449472.
It is an arithmetic number, because the mean of its divisors is an integer number (1752010275456).
Almost surely, 214011231122143 is an apocalyptic number.
14011231122143 is a deficient number, since it is larger than the sum of its proper divisors (4851081505).
14011231122143 is an equidigital number, since it uses as much as digits as its factorization.
14011231122143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 136333.
The product of its (nonzero) digits is 1152, while the sum is 26.
Adding to 14011231122143 its reverse (34122113211041), we get a palindrome (48133344333184).
The spelling of 14011231122143 in words is "fourteen trillion, eleven billion, two hundred thirty-one million, one hundred twenty-two thousand, one hundred forty-three".
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