140112333113 has 4 divisors (see below), whose sum is σ = 142487118480. Its totient is φ = 137737547748.

The previous prime is 140112333107. The next prime is 140112333149. The reversal of 140112333113 is 311333211041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140112333113 - 2¹² = 140112329017 is a prime.

It is a super-3 number, since 3×140112333113³ (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140112333013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1187392595 + ... + 1187392712.

It is an arithmetic number, because the mean of its divisors is an integer number (35621779620).

Almost surely, 2^140112333113 is an apocalyptic number.

It is an amenable number.

140112333113 is a deficient number, since it is larger than the sum of its proper divisors (2374785367).

140112333113 is an equidigital number, since it uses as much as digits as its factorization.

140112333113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2374785366.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 140112333113 its reverse (311333211041), we get a palindrome (451445544154).

The spelling of 140112333113 in words is "one hundred forty billion, one hundred twelve million, three hundred thirty-three thousand, one hundred thirteen".