1401211433 has 4 divisors (see below), whose sum is σ = 1405717248. Its totient is φ = 1396705620.

The previous prime is 1401211429. The next prime is 1401211499. The reversal of 1401211433 is 3341121041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3341121041 = 1181 ⋅2829061.

It is a cyclic number.

It is not a de Polignac number, because 1401211433 - 2² = 1401211429 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1401211633) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2252441 + ... + 2253062.

It is an arithmetic number, because the mean of its divisors is an integer number (351429312).

Almost surely, 2^1401211433 is an apocalyptic number.

It is an amenable number.

1401211433 is a deficient number, since it is larger than the sum of its proper divisors (4505815).

1401211433 is an equidigital number, since it uses as much as digits as its factorization.

1401211433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4505814.

The product of its (nonzero) digits is 288, while the sum is 20.

The square root of 1401211433 is about 37432.7588216525. The cubic root of 1401211433 is about 1119.0115196993.

Adding to 1401211433 its reverse (3341121041), we get a palindrome (4742332474).

The spelling of 1401211433 in words is "one billion, four hundred one million, two hundred eleven thousand, four hundred thirty-three".