Base | Representation |
---|---|
bin | 11111110111000011000101… |
… | …101101001001111000000111 |
3 | 200101010120020002202002022111 |
4 | 133313003011231021320013 |
5 | 121331231012440410231 |
6 | 1214003150523441451 |
7 | 41341334651164621 |
oct | 3767030555117007 |
9 | 611116202662274 |
10 | 140122330013191 |
11 | 407136013467a9 |
12 | 13870790986287 |
13 | 602562c54aba6 |
14 | 2685d57c75c11 |
15 | 112ed83ce14b1 |
hex | 7f70c5b49e07 |
140122330013191 has 2 divisors, whose sum is σ = 140122330013192. Its totient is φ = 140122330013190.
The previous prime is 140122330013161. The next prime is 140122330013221. The reversal of 140122330013191 is 191310033221041.
It is a balanced prime because it is at equal distance from previous prime (140122330013161) and next prime (140122330013221).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-140122330013191 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140122330013161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70061165006595 + 70061165006596.
It is an arithmetic number, because the mean of its divisors is an integer number (70061165006596).
Almost surely, 2140122330013191 is an apocalyptic number.
140122330013191 is a deficient number, since it is larger than the sum of its proper divisors (1).
140122330013191 is an equidigital number, since it uses as much as digits as its factorization.
140122330013191 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 31.
The spelling of 140122330013191 in words is "one hundred forty trillion, one hundred twenty-two billion, three hundred thirty million, thirteen thousand, one hundred ninety-one".
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