Base | Representation |
---|---|
bin | 1100101111100111101000… |
… | …1100001101100001000111 |
3 | 1211121120000122010001210012 |
4 | 3023321322030031201013 |
5 | 3314034023213402444 |
6 | 45445044154020435 |
7 | 2644231130133545 |
oct | 313717214154107 |
9 | 54546018101705 |
10 | 14012233340999 |
11 | 4512611471863 |
12 | 16a37b871771b |
13 | 7a846a54766a |
14 | 3662a506ad95 |
15 | 194754db1b9e |
hex | cbe7a30d847 |
14012233340999 has 8 divisors (see below), whose sum is σ = 14667962572800. Its totient is φ = 13369236715800.
The previous prime is 14012233340983. The next prime is 14012233341053. The reversal of 14012233340999 is 99904333221041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14012233340999 - 24 = 14012233340983 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14012233346999) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3183149399 + ... + 3183153800.
It is an arithmetic number, because the mean of its divisors is an integer number (1833495321600).
Almost surely, 214012233340999 is an apocalyptic number.
14012233340999 is a deficient number, since it is larger than the sum of its proper divisors (655729231801).
14012233340999 is an equidigital number, since it uses as much as digits as its factorization.
14012233340999 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6366303301.
The product of its (nonzero) digits is 1259712, while the sum is 50.
The spelling of 14012233340999 in words is "fourteen trillion, twelve billion, two hundred thirty-three million, three hundred forty thousand, nine hundred ninety-nine".
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