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1401241204103 = 13597879231871
BaseRepresentation
bin10100011001000000011…
…110111111010110000111
311221221211220112111102012
4110121000132333112013
5140424220222012403
62551415450004435
7203144030466626
oct24310036772607
94857756474365
101401241204103
114a0299147304
121a76a0a1671b
13a21a0ac6c80
144bb6b3c36bd
15266b20d8ed8
hex146407bf587

1401241204103 has 16 divisors (see below), whose sum is σ = 1534807142400. Its totient is φ = 1271363614560.

The previous prime is 1401241204087. The next prime is 1401241204123. The reversal of 1401241204103 is 3014021421041.

It is not a de Polignac number, because 1401241204103 - 24 = 1401241204087 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1401241204123) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5927258 + ... + 6159128.

It is an arithmetic number, because the mean of its divisors is an integer number (95925446400).

Almost surely, 21401241204103 is an apocalyptic number.

1401241204103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1401241204103 is a deficient number, since it is larger than the sum of its proper divisors (133565938297).

1401241204103 is a wasteful number, since it uses less digits than its factorization.

1401241204103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 239822.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 1401241204103 its reverse (3014021421041), we get a palindrome (4415262625144).

The spelling of 1401241204103 in words is "one trillion, four hundred one billion, two hundred forty-one million, two hundred four thousand, one hundred three".

Divisors: 1 13 59 767 7879 102427 231871 464861 3014323 6043193 13680389 177845057 1826911609 23749850917 107787784931 1401241204103