140130120203111 has 2 divisors, whose sum is σ = 140130120203112. Its totient is φ = 140130120203110.

The previous prime is 140130120203081. The next prime is 140130120203113. The reversal of 140130120203111 is 111302021031041.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140130120203111 is a prime.

Together with 140130120203113, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140130120203113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70065060101555 + 70065060101556.

It is an arithmetic number, because the mean of its divisors is an integer number (70065060101556).

Almost surely, 2^{140130120203111} is an apocalyptic number.

140130120203111 is a deficient number, since it is larger than the sum of its proper divisors (1).

140130120203111 is an equidigital number, since it uses as much as digits as its factorization.

140130120203111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 140130120203111 its reverse (111302021031041), we get a palindrome (251432141234152).

The spelling of 140130120203111 in words is "one hundred forty trillion, one hundred thirty billion, one hundred twenty million, two hundred three thousand, one hundred eleven".