Base | Representation |
---|---|
bin | 10100011001000100001… |
… | …011001100100110010101 |
3 | 11221222000020001101001112 |
4 | 110121010023030212111 |
5 | 140424332044434443 |
6 | 2551425541104405 |
7 | 203145412012325 |
oct | 24310413144625 |
9 | 4858006041045 |
10 | 1401303124373 |
11 | 4a0320099989 |
12 | 1a76b96b8105 |
13 | a21b0896c99 |
14 | 4bb75701285 |
15 | 266b776ab18 |
hex | 146442cc995 |
1401303124373 has 2 divisors, whose sum is σ = 1401303124374. Its totient is φ = 1401303124372.
The previous prime is 1401303124349. The next prime is 1401303124447. The reversal of 1401303124373 is 3734213031041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1018319137924 + 382983986449 = 1009118^2 + 618857^2 .
It is a cyclic number.
It is not a de Polignac number, because 1401303124373 - 210 = 1401303123349 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1401303124343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700651562186 + 700651562187.
It is an arithmetic number, because the mean of its divisors is an integer number (700651562187).
Almost surely, 21401303124373 is an apocalyptic number.
It is an amenable number.
1401303124373 is a deficient number, since it is larger than the sum of its proper divisors (1).
1401303124373 is an equidigital number, since it uses as much as digits as its factorization.
1401303124373 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18144, while the sum is 32.
The spelling of 1401303124373 in words is "one trillion, four hundred one billion, three hundred three million, one hundred twenty-four thousand, three hundred seventy-three".
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