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14013113010301 is a prime number
BaseRepresentation
bin1100101111101010111010…
…0111111000100001111101
31211121122021221100220012201
43023322232213320201331
53314042323412312201
645445311340231501
72644262001165226
oct313725647704175
954548257326181
1014013113010301
114512a22a78389
1216a3a0323b591
137a857a873242
14366349c1424d
151947a7224801
hexcbeae9f887d

14013113010301 has 2 divisors, whose sum is σ = 14013113010302. Its totient is φ = 14013113010300.

The previous prime is 14013113010277. The next prime is 14013113010349. The reversal of 14013113010301 is 10301031131041.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8642723902201 + 5370389108100 = 2939851^2 + 2317410^2 .

It is a cyclic number.

It is not a de Polignac number, because 14013113010301 - 211 = 14013113008253 is a prime.

It is a super-3 number, since 3×140131130103013 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14013113010371) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006556505150 + 7006556505151.

It is an arithmetic number, because the mean of its divisors is an integer number (7006556505151).

Almost surely, 214013113010301 is an apocalyptic number.

It is an amenable number.

14013113010301 is a deficient number, since it is larger than the sum of its proper divisors (1).

14013113010301 is an equidigital number, since it uses as much as digits as its factorization.

14013113010301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 14013113010301 its reverse (10301031131041), we get a palindrome (24314144141342).

The spelling of 14013113010301 in words is "fourteen trillion, thirteen billion, one hundred thirteen million, ten thousand, three hundred one".