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14013204341 = 42133285521
BaseRepresentation
bin11010000110100000…
…01000011101110101
31100011121022112112012
431003100020131311
5212144340014331
610234303334005
71004155162103
oct150320103565
940147275465
1014013204341
115a410a7914
122870bb1305
1314242830b6
1496d152c73
1557039082b
hex343408775

14013204341 has 4 divisors (see below), whose sum is σ = 14046490284. Its totient is φ = 13979918400.

The previous prime is 14013204277. The next prime is 14013204353. The reversal of 14013204341 is 14340231041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1305376900 + 12707827441 = 36130^2 + 112729^2 .

It is a cyclic number.

It is not a de Polignac number, because 14013204341 - 26 = 14013204277 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14013201341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16642340 + ... + 16643181.

It is an arithmetic number, because the mean of its divisors is an integer number (3511622571).

Almost surely, 214013204341 is an apocalyptic number.

It is an amenable number.

14013204341 is a deficient number, since it is larger than the sum of its proper divisors (33285943).

14013204341 is an equidigital number, since it uses as much as digits as its factorization.

14013204341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33285942.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 14013204341 its reverse (14340231041), we get a palindrome (28353435382).

The spelling of 14013204341 in words is "fourteen billion, thirteen million, two hundred four thousand, three hundred forty-one".

Divisors: 1 421 33285521 14013204341