140132104111 has 2 divisors, whose sum is σ = 140132104112. Its totient is φ = 140132104110.

The previous prime is 140132104103. The next prime is 140132104127. The reversal of 140132104111 is 111401231041.

It is a weak prime.

It is an emirp because it is prime and its reverse (111401231041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140132104111 - 2³ = 140132104103 is a prime.

It is a super-2 number, since 2×140132104111² (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140132101111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70066052055 + 70066052056.

It is an arithmetic number, because the mean of its divisors is an integer number (70066052056).

Almost surely, 2^140132104111 is an apocalyptic number.

140132104111 is a deficient number, since it is larger than the sum of its proper divisors (1).

140132104111 is an equidigital number, since it uses as much as digits as its factorization.

140132104111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 140132104111 its reverse (111401231041), we get a palindrome (251533335152).

The spelling of 140132104111 in words is "one hundred forty billion, one hundred thirty-two million, one hundred four thousand, one hundred eleven".