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14013233305 = 519147507719
BaseRepresentation
bin11010000110100000…
…01111100010011001
31100011121101000020221
431003100033202121
5212144341431210
610234304120041
71004155342411
oct150320174231
940147330227
1014013233305
115a41117655
122871006021
131424293336
1496d15d641
155703991da
hex34340f899

14013233305 has 8 divisors (see below), whose sum is σ = 17700926400. Its totient is φ = 10620555696.

The previous prime is 14013233287. The next prime is 14013233317. The reversal of 14013233305 is 50333231041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14013233305 - 27 = 14013233177 is a prime.

It is a super-2 number, since 2×140132333052 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14013233305.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 73753765 + ... + 73753954.

It is an arithmetic number, because the mean of its divisors is an integer number (2212615800).

Almost surely, 214013233305 is an apocalyptic number.

It is an amenable number.

14013233305 is a deficient number, since it is larger than the sum of its proper divisors (3687693095).

14013233305 is a wasteful number, since it uses less digits than its factorization.

14013233305 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 147507743.

The product of its (nonzero) digits is 3240, while the sum is 25.

Adding to 14013233305 its reverse (50333231041), we get a palindrome (64346464346).

The spelling of 14013233305 in words is "fourteen billion, thirteen million, two hundred thirty-three thousand, three hundred five".

Divisors: 1 5 19 95 147507719 737538595 2802646661 14013233305