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14013320441 is a prime number
BaseRepresentation
bin11010000110100001…
…00100110011111001
31100011121112102210012
431003100210303321
5212144402223231
610234310031305
71004156154431
oct150320446371
940147472705
1014013320441
115a4117706a
122871048535
1314242c3bb3
1496d1832c1
155703b4e2b
hex343424cf9

14013320441 has 2 divisors, whose sum is σ = 14013320442. Its totient is φ = 14013320440.

The previous prime is 14013320429. The next prime is 14013320443. The reversal of 14013320441 is 14402331041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13962967225 + 50353216 = 118165^2 + 7096^2 .

It is a cyclic number.

It is not a de Polignac number, because 14013320441 - 214 = 14013304057 is a prime.

Together with 14013320443, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14013320443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006660220 + 7006660221.

It is an arithmetic number, because the mean of its divisors is an integer number (7006660221).

Almost surely, 214013320441 is an apocalyptic number.

It is an amenable number.

14013320441 is a deficient number, since it is larger than the sum of its proper divisors (1).

14013320441 is an equidigital number, since it uses as much as digits as its factorization.

14013320441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 14013320441 its reverse (14402331041), we get a palindrome (28415651482).

The spelling of 14013320441 in words is "fourteen billion, thirteen million, three hundred twenty thousand, four hundred forty-one".