Base | Representation |
---|---|
bin | 11010000110100001… |
… | …00100110011111001 |
3 | 1100011121112102210012 |
4 | 31003100210303321 |
5 | 212144402223231 |
6 | 10234310031305 |
7 | 1004156154431 |
oct | 150320446371 |
9 | 40147472705 |
10 | 14013320441 |
11 | 5a4117706a |
12 | 2871048535 |
13 | 14242c3bb3 |
14 | 96d1832c1 |
15 | 5703b4e2b |
hex | 343424cf9 |
14013320441 has 2 divisors, whose sum is σ = 14013320442. Its totient is φ = 14013320440.
The previous prime is 14013320429. The next prime is 14013320443. The reversal of 14013320441 is 14402331041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13962967225 + 50353216 = 118165^2 + 7096^2 .
It is a cyclic number.
It is not a de Polignac number, because 14013320441 - 214 = 14013304057 is a prime.
Together with 14013320443, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (14013320443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006660220 + 7006660221.
It is an arithmetic number, because the mean of its divisors is an integer number (7006660221).
Almost surely, 214013320441 is an apocalyptic number.
It is an amenable number.
14013320441 is a deficient number, since it is larger than the sum of its proper divisors (1).
14013320441 is an equidigital number, since it uses as much as digits as its factorization.
14013320441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 14013320441 its reverse (14402331041), we get a palindrome (28415651482).
The spelling of 14013320441 in words is "fourteen billion, thirteen million, three hundred twenty thousand, four hundred forty-one".
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