Search a number
-
+
140133311 is a prime number
BaseRepresentation
bin10000101101001…
…00001110111111
3100202200111202122
420112210032333
5241333231221
621523313155
73321053633
oct1026441677
9322614678
10140133311
117211325a
123ab1b7bb
1323055c26
141487adc3
15c480eab
hex85a43bf

140133311 has 2 divisors, whose sum is σ = 140133312. Its totient is φ = 140133310.

The previous prime is 140133289. The next prime is 140133373. The reversal of 140133311 is 113331041.

It is a weak prime.

It is an emirp because it is prime and its reverse (113331041) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140133311 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 140133311.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140133391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70066655 + 70066656.

It is an arithmetic number, because the mean of its divisors is an integer number (70066656).

Almost surely, 2140133311 is an apocalyptic number.

140133311 is a deficient number, since it is larger than the sum of its proper divisors (1).

140133311 is an equidigital number, since it uses as much as digits as its factorization.

140133311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 140133311 is about 11837.7916437146. The cubic root of 140133311 is about 519.4141713715.

Adding to 140133311 its reverse (113331041), we get a palindrome (253464352).

The spelling of 140133311 in words is "one hundred forty million, one hundred thirty-three thousand, three hundred eleven".