Search a number
-
+
14013400211 = 15139925649
BaseRepresentation
bin11010000110100001…
…11000010010010011
31100011121200111012122
431003100320102103
5212144412301321
610234311444455
71004156636126
oct150320702223
940147614178
1014013400211
115a41220a98
12287108672b
1314243212b5
1496d1a43bd
155703cd8ab
hex343438493

14013400211 has 4 divisors (see below), whose sum is σ = 14014341000. Its totient is φ = 14012459424.

The previous prime is 14013400207. The next prime is 14013400217. The reversal of 14013400211 is 11200431041.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11200431041 = 41926731339.

It is a cyclic number.

It is not a de Polignac number, because 14013400211 - 22 = 14013400207 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14013400211.

It is not an unprimeable number, because it can be changed into a prime (14013400217) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 447686 + ... + 477963.

It is an arithmetic number, because the mean of its divisors is an integer number (3503585250).

Almost surely, 214013400211 is an apocalyptic number.

14013400211 is a deficient number, since it is larger than the sum of its proper divisors (940789).

14013400211 is an equidigital number, since it uses as much as digits as its factorization.

14013400211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 940788.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 14013400211 its reverse (11200431041), we get a palindrome (25213831252).

The spelling of 14013400211 in words is "fourteen billion, thirteen million, four hundred thousand, two hundred eleven".

Divisors: 1 15139 925649 14013400211