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14013412011 = 321557045779
BaseRepresentation
bin11010000110100001…
…11011001010101011
31100011121201002101200
431003100323022223
5212144413141021
610234312015243
71004160015414
oct150320731253
940147632350
1014013412011
115a41229945
122871091523
131424326791
1496d1a880b
155703d2126
hex34343b2ab

14013412011 has 6 divisors (see below), whose sum is σ = 20241595140. Its totient is φ = 9342274668.

The previous prime is 14013411991. The next prime is 14013412033. The reversal of 14013412011 is 11021431041.

14013412011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 14013412011 - 215 = 14013379243 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14013412051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 778522881 + ... + 778522898.

It is an arithmetic number, because the mean of its divisors is an integer number (3373599190).

Almost surely, 214013412011 is an apocalyptic number.

14013412011 is a deficient number, since it is larger than the sum of its proper divisors (6228183129).

14013412011 is a wasteful number, since it uses less digits than its factorization.

14013412011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1557045785 (or 1557045782 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 14013412011 its reverse (11021431041), we get a palindrome (25034843052).

The spelling of 14013412011 in words is "fourteen billion, thirteen million, four hundred twelve thousand, eleven".

Divisors: 1 3 9 1557045779 4671137337 14013412011