Base | Representation |
---|---|
bin | 11010000110100010… |
… | …00000000011110010 |
3 | 1100011121202002212212 |
4 | 31003101000003302 |
5 | 212144414311200 |
6 | 10234312252122 |
7 | 1004160131012 |
oct | 150321000362 |
9 | 40147662785 |
10 | 14013432050 |
11 | 5a41242a02 |
12 | 28710a1042 |
13 | 1424332937 |
14 | 96d1b1c42 |
15 | 5703d8035 |
hex | 3434400f2 |
14013432050 has 24 divisors (see below), whose sum is σ = 26068131012. Its totient is φ = 5604696000.
The previous prime is 14013431989. The next prime is 14013432071. The reversal of 14013432050 is 5023431041.
It can be written as a sum of positive squares in 6 ways, for example, as 3324560281 + 10688871769 = 57659^2 + 103387^2 .
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 713360 + ... + 732740.
Almost surely, 214013432050 is an apocalyptic number.
14013432050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
14013432050 is a deficient number, since it is larger than the sum of its proper divisors (12054698962).
14013432050 is a wasteful number, since it uses less digits than its factorization.
14013432050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33854 (or 33849 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 14013432050 its reverse (5023431041), we get a palindrome (19036863091).
The spelling of 14013432050 in words is "fourteen billion, thirteen million, four hundred thirty-two thousand, fifty".
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