Base | Representation |
---|---|
bin | 10100011001000110111… |
… | …110001101001000000110 |
3 | 11221222010111100110100012 |
4 | 110121012332031020012 |
5 | 140424431103102220 |
6 | 2551434334550222 |
7 | 203146521614540 |
oct | 24310676151006 |
9 | 4858114313305 |
10 | 1401350050310 |
11 | 4a0344630051 |
12 | 1a7711368372 |
13 | a21ba517102 |
14 | 4bb7ba38690 |
15 | 266bb939ac5 |
hex | 14646f8d206 |
1401350050310 has 32 divisors (see below), whose sum is σ = 2882866628160. Its totient is φ = 480447977472.
The previous prime is 1401350050297. The next prime is 1401350050411. The reversal of 1401350050310 is 130500531041.
It is a super-3 number, since 3×14013500503103 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2095742 + ... + 2682318.
It is an arithmetic number, because the mean of its divisors is an integer number (90089582130).
Almost surely, 21401350050310 is an apocalyptic number.
1401350050310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1401350050310 is an abundant number, since it is smaller than the sum of its proper divisors (1481516577850).
1401350050310 is a wasteful number, since it uses less digits than its factorization.
1401350050310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 620720.
The product of its (nonzero) digits is 900, while the sum is 23.
Adding to 1401350050310 its reverse (130500531041), we get a palindrome (1531850581351).
The spelling of 1401350050310 in words is "one trillion, four hundred one billion, three hundred fifty million, fifty thousand, three hundred ten".
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