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1401565017101 is a prime number
BaseRepresentation
bin10100011001010011110…
…010001111010000001101
311221222200110211220100012
4110121103302033100031
5140430401121021401
62551511534243005
7203155042036064
oct24312362172015
94858613756305
101401565017101
114a0444a05857
121a7771356465
13a2222c118b2
144bb9c3d51db
15266d074d8bb
hex14653c8f40d

1401565017101 has 2 divisors, whose sum is σ = 1401565017102. Its totient is φ = 1401565017100.

The previous prime is 1401565017091. The next prime is 1401565017103. The reversal of 1401565017101 is 1017105651041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1005710128201 + 395854888900 = 1002851^2 + 629170^2 .

It is a cyclic number.

It is not a de Polignac number, because 1401565017101 - 26 = 1401565017037 is a prime.

It is a super-2 number, since 2×14015650171012 (a number of 25 digits) contains 22 as substring.

Together with 1401565017103, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1401565017103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700782508550 + 700782508551.

It is an arithmetic number, because the mean of its divisors is an integer number (700782508551).

Almost surely, 21401565017101 is an apocalyptic number.

It is an amenable number.

1401565017101 is a deficient number, since it is larger than the sum of its proper divisors (1).

1401565017101 is an equidigital number, since it uses as much as digits as its factorization.

1401565017101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4200, while the sum is 32.

The spelling of 1401565017101 in words is "one trillion, four hundred one billion, five hundred sixty-five million, seventeen thousand, one hundred one".