14018831471 has 2 divisors, whose sum is σ = 14018831472. Its totient is φ = 14018831470.

The previous prime is 14018831461. The next prime is 14018831473. The reversal of 14018831471 is 17413881041.

It is a strong prime.

It is an emirp because it is prime and its reverse (17413881041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14018831471 - 2²² = 14014637167 is a prime.

It is a super-3 number, since 3×14018831471³ (a number of 31 digits) contains 333 as substring.

Together with 14018831473, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14018831473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7009415735 + 7009415736.

It is an arithmetic number, because the mean of its divisors is an integer number (7009415736).

Almost surely, 2^14018831471 is an apocalyptic number.

14018831471 is a deficient number, since it is larger than the sum of its proper divisors (1).

14018831471 is an equidigital number, since it uses as much as digits as its factorization.

14018831471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21504, while the sum is 38.

The spelling of 14018831471 in words is "fourteen billion, eighteen million, eight hundred thirty-one thousand, four hundred seventy-one".