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1401938602399 is a prime number
BaseRepresentation
bin10100011001101010000…
…011010110100110011111
311222000122111211000000201
4110121222003112212133
5140432132240234044
62552013001404331
7203200226334046
oct24315203264637
94860574730021
101401938602399
114a0616879a35
121a78564996a7
13a228243509a
144bbd5c8155d
15267034457d4
hex1466a0d699f

1401938602399 has 2 divisors, whose sum is σ = 1401938602400. Its totient is φ = 1401938602398.

The previous prime is 1401938602367. The next prime is 1401938602429. The reversal of 1401938602399 is 9932068391041.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (9932068391041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1401938602399 - 25 = 1401938602367 is a prime.

It is a super-2 number, since 2×14019386023992 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1401938603399) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700969301199 + 700969301200.

It is an arithmetic number, because the mean of its divisors is an integer number (700969301200).

Almost surely, 21401938602399 is an apocalyptic number.

1401938602399 is a deficient number, since it is larger than the sum of its proper divisors (1).

1401938602399 is an equidigital number, since it uses as much as digits as its factorization.

1401938602399 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2519424, while the sum is 55.

The spelling of 1401938602399 in words is "one trillion, four hundred one billion, nine hundred thirty-eight million, six hundred two thousand, three hundred ninety-nine".