Base | Representation |
---|---|
bin | 1100110000000100101011… |
… | …1111111010000101101111 |
3 | 1211122022011002202122212201 |
4 | 3030001022333322011233 |
5 | 3314201011032134020 |
6 | 45452414044042331 |
7 | 2644625310436603 |
oct | 314011277720557 |
9 | 54568132678781 |
10 | 14020031521135 |
11 | 4515953323a32 |
12 | 16a52142333a7 |
13 | 7a9111017033 |
14 | 3668049db503 |
15 | 194a5e7e3a0a |
hex | cc04affa16f |
14020031521135 has 4 divisors (see below), whose sum is σ = 16824037825368. Its totient is φ = 11216025216904.
The previous prime is 14020031521103. The next prime is 14020031521183. The reversal of 14020031521135 is 53112513002041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14020031521135 - 25 = 14020031521103 is a prime.
It is a super-2 number, since 2×140200315211352 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1402003152109 + ... + 1402003152118.
It is an arithmetic number, because the mean of its divisors is an integer number (4206009456342).
Almost surely, 214020031521135 is an apocalyptic number.
14020031521135 is a deficient number, since it is larger than the sum of its proper divisors (2804006304233).
14020031521135 is an equidigital number, since it uses as much as digits as its factorization.
14020031521135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2804006304232.
The product of its (nonzero) digits is 3600, while the sum is 28.
Adding to 14020031521135 its reverse (53112513002041), we get a palindrome (67132544523176).
The spelling of 14020031521135 in words is "fourteen trillion, twenty billion, thirty-one million, five hundred twenty-one thousand, one hundred thirty-five".
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