140200502200331 has 2 divisors, whose sum is σ = 140200502200332. Its totient is φ = 140200502200330.

The previous prime is 140200502200321. The next prime is 140200502200333. The reversal of 140200502200331 is 133002205002041.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140200502200331 is a prime.

It is a super-2 number, since 2×140200502200331² (a number of 29 digits) contains 22 as substring.

Together with 140200502200333, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 140200502200297 and 140200502200306.

It is not a weakly prime, because it can be changed into another prime (140200502200333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70100251100165 + 70100251100166.

It is an arithmetic number, because the mean of its divisors is an integer number (70100251100166).

Almost surely, 2^{140200502200331} is an apocalyptic number.

140200502200331 is a deficient number, since it is larger than the sum of its proper divisors (1).

140200502200331 is an equidigital number, since it uses as much as digits as its factorization.

140200502200331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 140200502200331 its reverse (133002205002041), we get a palindrome (273202707202372).

The spelling of 140200502200331 in words is "one hundred forty trillion, two hundred billion, five hundred two million, two hundred thousand, three hundred thirty-one".