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140202017 is a prime number
BaseRepresentation
bin10000101101101…
…01000000100001
3100202211000000022
420112311000201
5241342431032
621525003225
73321461144
oct1026650041
9322730008
10140202017
117215a93a
123ab53515
132307b297
141489805b
15c496512
hex85b5021

140202017 has 2 divisors, whose sum is σ = 140202018. Its totient is φ = 140202016.

The previous prime is 140201983. The next prime is 140202019. The reversal of 140202017 is 710202041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108347281 + 31854736 = 10409^2 + 5644^2 .

It is a cyclic number.

It is not a de Polignac number, because 140202017 - 26 = 140201953 is a prime.

Together with 140202019, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 140201986 and 140202004.

It is not a weakly prime, because it can be changed into another prime (140202019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70101008 + 70101009.

It is an arithmetic number, because the mean of its divisors is an integer number (70101009).

Almost surely, 2140202017 is an apocalyptic number.

It is an amenable number.

140202017 is a deficient number, since it is larger than the sum of its proper divisors (1).

140202017 is an equidigital number, since it uses as much as digits as its factorization.

140202017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 112, while the sum is 17.

The square root of 140202017 is about 11840.6932651767. The cubic root of 140202017 is about 519.4990454082.

Adding to 140202017 its reverse (710202041), we get a palindrome (850404058).

The spelling of 140202017 in words is "one hundred forty million, two hundred two thousand, seventeen".