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140203113 = 3193242147
BaseRepresentation
bin10000101101101…
…01010001101001
3100202211001111220
420112311101221
5241342444423
621525012253
73321464301
oct1026652151
9322731456
10140203113
1172160746
123ab54089
132307b92b
1414898601
15c4969e3
hex85b5469

140203113 has 8 divisors (see below), whose sum is σ = 187906848. Its totient is φ = 92984064.

The previous prime is 140203099. The next prime is 140203157. The reversal of 140203113 is 311302041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 140203113 - 222 = 136008809 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 140203092 and 140203101.

It is not an unprimeable number, because it can be changed into a prime (140203183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 120495 + ... + 121652.

It is an arithmetic number, because the mean of its divisors is an integer number (23488356).

Almost surely, 2140203113 is an apocalyptic number.

It is an amenable number.

140203113 is a deficient number, since it is larger than the sum of its proper divisors (47703735).

140203113 is a wasteful number, since it uses less digits than its factorization.

140203113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 242343.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 140203113 is about 11840.7395461601. The cubic root of 140203113 is about 519.5003990965.

Adding to 140203113 its reverse (311302041), we get a palindrome (451505154).

The spelling of 140203113 in words is "one hundred forty million, two hundred three thousand, one hundred thirteen".

Divisors: 1 3 193 579 242147 726441 46734371 140203113