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140203131335 = 5193213767987
BaseRepresentation
bin1000001010010011000…
…0100000000111000111
3111101212222221000112222
42002210300200013013
54244114000200320
6144224115402555
713062235644641
oct2024460400707
9441788830488
10140203131335
1154507015783
12232098b345b
13102b49a4657
146b005c7891
1539a8998825
hex20a4c201c7

140203131335 has 16 divisors (see below), whose sum is σ = 169197112416. Its totient is φ = 111527497728.

The previous prime is 140203131307. The next prime is 140203131349. The reversal of 140203131335 is 533131302041.

It is a cyclic number.

It is not a de Polignac number, because 140203131335 - 234 = 123023262151 is a prime.

It is a super-2 number, since 2×1402031313352 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2028212 + ... + 2096198.

It is an arithmetic number, because the mean of its divisors is an integer number (10574819526).

Almost surely, 2140203131335 is an apocalyptic number.

140203131335 is a deficient number, since it is larger than the sum of its proper divisors (28993981081).

140203131335 is a wasteful number, since it uses less digits than its factorization.

140203131335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70322.

The product of its (nonzero) digits is 3240, while the sum is 26.

Adding to 140203131335 its reverse (533131302041), we get a palindrome (673334433376).

The spelling of 140203131335 in words is "one hundred forty billion, two hundred three million, one hundred thirty-one thousand, three hundred thirty-five".

Divisors: 1 5 193 965 2137 10685 67987 339935 412441 2062205 13121491 65607455 145288219 726441095 28040626267 140203131335