Base | Representation |
---|---|
bin | 11111111000011000110110… |
… | …001011100000011101010100 |
3 | 200101110100220101222201021212 |
4 | 133320120312023200131110 |
5 | 121334233103300101122 |
6 | 1214113340014000552 |
7 | 41351104552366415 |
oct | 3770306613403524 |
9 | 611410811881255 |
10 | 140214411331412 |
11 | 407496638a5aa0 |
12 | 138865aa7a6158 |
13 | 60312156198c2 |
14 | 268a5b135980c |
15 | 1132472c44ce2 |
hex | 7f86362e0754 |
140214411331412 has 96 divisors (see below), whose sum is σ = 282454549977600. Its totient is φ = 60232991299200.
The previous prime is 140214411331391. The next prime is 140214411331439. The reversal of 140214411331412 is 214133114412041.
140214411331412 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×1402144113314122 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 712594139 + ... + 712790877.
It is an arithmetic number, because the mean of its divisors is an integer number (2942234895600).
Almost surely, 2140214411331412 is an apocalyptic number.
It is an amenable number.
140214411331412 is an abundant number, since it is smaller than the sum of its proper divisors (142240138646188).
140214411331412 is a wasteful number, since it uses less digits than its factorization.
140214411331412 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 198837 (or 198835 counting only the distinct ones).
The product of its (nonzero) digits is 9216, while the sum is 32.
Adding to 140214411331412 its reverse (214133114412041), we get a palindrome (354347525743453).
The spelling of 140214411331412 in words is "one hundred forty trillion, two hundred fourteen billion, four hundred eleven million, three hundred thirty-one thousand, four hundred twelve".
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