Base | Representation |
---|---|
bin | 10100011001111001111… |
… | …000100100100000011111 |
3 | 11222001100000121022211212 |
4 | 110121321320210200133 |
5 | 140433203234224411 |
6 | 2552055210335035 |
7 | 203206633065605 |
oct | 24317170444037 |
9 | 4861300538755 |
10 | 1402204211231 |
11 | 4a07427a386a |
12 | 1a790b42a47b |
13 | a22c5481285 |
14 | 4bc1d261875 |
15 | 2671b90e68b |
hex | 14679e2481f |
1402204211231 has 2 divisors, whose sum is σ = 1402204211232. Its totient is φ = 1402204211230.
The previous prime is 1402204211209. The next prime is 1402204211251. The reversal of 1402204211231 is 1321124022041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1402204211231 - 222 = 1402200016927 is a prime.
It is a super-2 number, since 2×14022042112312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1402204211197 and 1402204211206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1402204211251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701102105615 + 701102105616.
It is an arithmetic number, because the mean of its divisors is an integer number (701102105616).
Almost surely, 21402204211231 is an apocalyptic number.
1402204211231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1402204211231 is an equidigital number, since it uses as much as digits as its factorization.
1402204211231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 1402204211231 its reverse (1321124022041), we get a palindrome (2723328233272).
The spelling of 1402204211231 in words is "one trillion, four hundred two billion, two hundred four million, two hundred eleven thousand, two hundred thirty-one".
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