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140221011041 is a prime number
BaseRepresentation
bin1000001010010111010…
…0101101010001100001
3111101221020120101220022
42002211310231101201
54244133034323131
6144225554523225
713062543633236
oct2024564552141
9441836511808
10140221011041
1154516117aa1
1223213896515
13102b85c4967
146b02b1d78d
1539aa32b37b
hex20a5d2d461

140221011041 has 2 divisors, whose sum is σ = 140221011042. Its totient is φ = 140221011040.

The previous prime is 140221010987. The next prime is 140221011043. The reversal of 140221011041 is 140110122041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101413587025 + 38807424016 = 318455^2 + 196996^2 .

It is a cyclic number.

It is not a de Polignac number, because 140221011041 - 26 = 140221010977 is a prime.

Together with 140221011043, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (140221011043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70110505520 + 70110505521.

It is an arithmetic number, because the mean of its divisors is an integer number (70110505521).

Almost surely, 2140221011041 is an apocalyptic number.

It is an amenable number.

140221011041 is a deficient number, since it is larger than the sum of its proper divisors (1).

140221011041 is an equidigital number, since it uses as much as digits as its factorization.

140221011041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 140221011041 its reverse (140110122041), we get a palindrome (280331133082).

The spelling of 140221011041 in words is "one hundred forty billion, two hundred twenty-one million, eleven thousand, forty-one".